Q26: The motion of a human body through space can be modeled as the motion of a particle at the body’s cen- ter of mass as we will study in Chapter 9. The compo- nents of the displacement of an athlete’s center of mass from the beginning to the end of a certain jump are described by the equations xf = + (m/s)(cos )t m = m +( m/s) (sin )t - ( m/s^2) t^2 where t is in seconds and is the time at which the ath- lete ends the jump. Identify
(a) the athlete’s position and
(b) his vector velocity at the takeoff point. (c) How far did he jump?